x^2+16x-58=-10

Solution for x^2+16x-58=-10 equation:

x^2+16x-58=-10

We move all terms to the left:

x^2+16x-58-(-10)=0

We add all the numbers together, and all the variables

x^2+16x-48=0

a = 1; b = 16; c = -48;
Δ = b2-4ac
Δ = 162-4·1·(-48)
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{7}}{2*1}=\frac{-16-8\sqrt{7}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{7}}{2*1}=\frac{-16+8\sqrt{7}}{2}
$